Short Problem Definition:
Given a word w, rearrange the letters of w to construct another word in such a way that is lexicographically greater than w. In case of multiple possible answers, find the lexicographically smallest one among them.
time complexity is
space complexity is
This task challenges us to find the next permutation of any given array. There are many implementations available online and it is worthwhile comparing them . I would recommend reading the article by Nayuki or re-implementing the std::next_permutation.
def next_permutation(arr): # Find non-increasing suffix i = len(arr) - 1 while i > 0 and arr[i - 1] >= arr[i]: i -= 1 if i <= 0: return False # Find successor to pivot j = len(arr) - 1 while arr[j] <= arr[i - 1]: j -= 1 arr[i - 1], arr[j] = arr[j], arr[i - 1] # Reverse suffix arr[i : ] = arr[len(arr) - 1 : i - 1 : -1] return True def main(): t = input() for _ in xrange(t): s = list(raw_input()) if next_permutation(s): print "".join(s) else: print "no answer" if __name__ == '__main__': main()