Short Problem Definition:
You are given an integer N. Find the digits in this number that exactly divide N (division that leaves 0 as remainder) and display their count. For N=24, there are 2 digits (2 & 4). Both of these digits exactly divide 24. So our answer is 2.
time complexity is
space complexity is
Just follow the problem description. The problem can be optimized by creating a map of digits and their counts.
#!/usr/bin/py if __name__ == '__main__': t = input() for _ in xrange(t): a = input() count = 0 for i in list(str(a)): if int(i) != 0 and a % int(i) == 0: count += 1 print count